Using String Sequences with DDS_DynamicData

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Using String Sequences with DDS_DynamicData

Hey,

 

I'm currently using DDS_DynamicData to map my application's type to DDS_DynamicData. However, my application also uses Arrays of strings, which I've mapped over Sequences of Strings in DDS_DynamicData. I've just stumbled upon the problem that I cannot call "DDS_DynamicData::set_string_seq" on a DDS_DynamicData object.

I already know that I can bind to the sequence and set each sequence member sepparately, but I cannot do this in my application because the data that needs to be mapped to DDS_DynamicData comes as a contiguous buffer. 

For example, I'm using a sequence of DDS_TK_CHAR in order to map strings, and then I'm doing the following on it:

DDS_CharSeq charSeq;
charSeq.ensure_length(stringLength, stringLength);
std::memcpy(charSeq.get_contiguous_buffer(), stringData, stringLength);
retCode = sendData->set_char_seq(memberName, DDS_DYNAMIC_DATA_MEMBER_ID_UNSPECIFIED, charSeq);

This is something I want to do for strings as well:

DDS_StringSeq stringSeq;

stringSeq.ensureLength(stringArrayLength, stringArrayLength);

std::memcpy(stringSeq.get_contiguous_buffer(), stringArrayData, stringArrayLength);

retcode = sendData->set_string_Seq(memberName, DDS_DYNAMIC_DATA_MEMBER_ID_UNSPECIFIED, stringSeq);

 

Can someone tell me if there's a way to set a sequence of strings this way?

Thank you.

Best,

Andrei

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Fernando Garcia's picture
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Posts: 199

Hi Andrey,

Because strings are complex types, there is no API to set a sequence of Strings with one call like you do with the sequence of characters.

I think the only solution is bind and set member by member. You mentioned that is impossible in your case, why is that the case?

Thanks,
Fernando.

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Last seen: 6 years 9 months ago
Joined: 03/03/2015
Posts: 19

Hey Fernando,

My string array comes as a byte array. However, I think I can get the length of each array element size and set the string element by binding and setting each member by member. I've postponed this fix for now but I expect I will get back to it in some time.

 

Thank you for the answer :)

Best,

Andrei